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 Post subject: Size of archive parts for rar.
PostPosted: November 30th, 2018, 3:59 pm 

Joined: January 13th, 2014, 7:59 pm
Posts: 91
I do not know if this is a Bug, so I will ask
in the settings I want my files to be divided a party of size 2047 MB that is almost 2 GB

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and divides me a party of size 1.91 GB

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 Post subject: Re: Size of parties
PostPosted: November 30th, 2018, 4:17 pm 
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Joined: March 10th, 2011, 11:14 pm
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Hi,

looks like WinRar understands option -v2047M literally as "2 047 000 000 bytes" (just tested).

2 047 000 000 bytes is 2047000000 / 1024 / 1024 / 1024 = ~1.91GB.

If you want 1.99GB you could calculate it as: 1.99 * 1024 * 1024 * 1024 = ~2 136 746 229 or ~ 2137mb.

So just enter 2137 in that field and it will compress for max of 1.99GB parts (also tested).

EDIT: if anyone needs 0.99 GB then: 0.99 * 1024 * 1024 * 1024 = ~1 063 004 406 or ~ 1063mb.

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 Post subject: Re: Size of archive parts for rar.
PostPosted: November 30th, 2018, 7:55 pm 

Joined: January 13th, 2014, 7:59 pm
Posts: 91
Thanks for the info


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